Talk:Benderama

God Entity
I believe the voice for the God entity is used in this episode, I'm wondering if it's a purposeful reference to that character. When Bender is defeated in the fight against the ugly giant, light appears on Bender and a voice is heard saying "Walk into the light Bender." and Bender replies saying "Aww, man, do I have to walk?!" Polantaris 07:56, 24 June 2011 (CEST)
 * I'm not sure. It sounds more like a general, deep voice to me. I don't see why the Galactic Entity would bother talking to the big Bender. - akitalk 08:08, 24 June 2011 (CEST)
 * Seeing as no-one replied for quite a while, I took away the information about Galactic Entity appearing. Before re-adding it, please restart this discussion. - akitalk 13:30, 26 June 2011 (CEST)

The Formula
The mass of an individual generation is just 60% the mass of a bender in the previous generation. So given the original mass M_0, the mass of a Bender in generation n should be M_0*0.6^(n-1) (assuming n starts at 1). So, given 2^(n-1) Benders per generation, the total mass should be the sum from n=1 to N of M_0*(1.2)^(n-1) = M_0*(1.2^n -1/)0.2 which does not converge as N -> infinity. (1.2 > 1). The article currently says that the mass changes by the cube of the scaling factor. Did I miss something in the episode, or should the mass of a Bender in generation n just be the 60% the mass of a bender in generation n-1 (consider the first duplication: In generation 2, there are 2 Benders, each massing 60% of the original. So, the mass of this generation is M_0*0.6*2; adding this to the original M_0 matches the formula above, 2.2*M_0).
 * Mass is directly proportional to the cube of length; that is, mass scales directly with volume. If Bender's height is scaled by 60% (and all other linear measures are similarly scaled by 60%), then Bender's volume is 60%^3 = 21.6% of the volume of the original Bender, thus 21.6% of the mass of the original.  This has nothing to do with anything in the episode, but is rather a basic result from geometry or physics.  Imagine that you have a perfect cube of material that measures 1 m on a side, and weighs 1 kg (thus having a density of 1 kg/m^3).  Now make a scale copy of that cube that is 50% smaller.  The new cube is half a meter on a side, and still has a density of 1 kg/m^3.  Mass is density times volume, thus the new cube has a mass of (1 kg/m^3)*(0.5 m)^3 = 0.125 kg.   --71.83.120.33 17:19, 25 June 2011 (CEST)
 * I interpreted it as 60% the volume, which would imply 60% as massive. I'll watch the episode again, but you're probably right that it's a 3/5 scale length ratio.
 * In general, when people talk about scale, they are referring to linear scale. Hence a 1:45 scale model of a train would be a model train that is 1/45th of the length of a full sized train.  Thus typical usage would suggest that Bender is scaled by a linear factor of 60% (i.e. all linear measurements are scaled to 60%).  If we assume that volume is scaled by 60%, then linear measures would be scaled by about 84% (the cube root of 60%).  Visually, it would appear to me that the copies are 60% of the height of the original, rather than 84%.  --71.83.120.33 19:27, 25 June 2011 (CEST)
 * I understand what you're saying; I probably just wan't paying too much attention to detail the first time around (it is a comedy cartoon, after all!). Thank you for pointing it out.
 * Maybe I missed it, but was there a rule that each Bender could only reproduce once to make 2 "children"? Because if the Bender's could reproduce indefinitely, the formula doesn't apply.
 * Each Bender could multiply into 2 more benders, but since the copying machine was in Bender, it too would get duplicated, so they could duplicate infinitely as long as they find matter to stuff into the machine. Polantaris 11:55, 26 June 2011 (CEST)
 * I don't think that it was ever explicitly stated that each Bender could only make two copies. However, if that limit is not in place, it doesn't make any sense to talk about limiting series.  The original Bender could reproduce over and over again, consuming an infinite amount of matter.  So, while such a rule was never explicitly stated, it seemed implicit in the way that the situation was described. --71.83.120.33 19:31, 26 June 2011 (CEST)

Convergence or Divergence?
Hi, guys! In spite of being a total math geek, I have tried to stay away from this discussion. However, it has sort of started to mess up the actual article, with contradictions and personal incredulity and whathaveyou. So, here goes: Why don't you guys try to settle things here on the talk page, create a badass text that everyone agrees on, and then put it back on the article? Until then, please don't mention the formula in the trivia or goof sections. Thanks!

The current text (that I now removed) was this:


 * The formula that the professor shows is incorrect. The total mass of all of the Benders should be the sum of the number of Benders in each generation times the mass of each Bender in that generation. The number of Benders in each generation is twice the number of Benders in the previous generation, thus there are 2^n Benders in the nth generation.  Mass changes as the cube of the scaling factor, thus each Bender weighs 0.6^3=21.6% of what its parent weighs.  If we assume that the mass of the original Bender is M_0, then the mass of an nth generation Bender is M_0*0.216^n.  Thus the mass of all of the Benders after an infinite number of generations is the sum of terms of the form 2^n*(M_0*0.216^n), where n goes from 0 to infinity.  This series does converge.
 * In fact, the math does work out correctly. The equation shown by Farnsworth correctly describes a (divergent), so the only question would be whether this sequence accurately describes the scaling of Bender. With the second generation (n=1), the formula predicts that each Bender will weight 1/4 of the original Bender. If that is true, the linear scale of each 2nd-gen Bender would be the cube root of 1/4, which works out to about 0.63 with rounding. Therefore, Bender's "60 percent scale" statement is roughly accurate for the first generation. The criticism above assumes that "each" generation is a 60 percent scale replica of its parent, yet Bender never claims that to be the case; he only remarks on the 1st generation, for which the statement is roughly correct with rounding.

Again, thanks. - akitalk 13:15, 27 June 2011 (CEST)


 * I agree that discussion of the mathematics should remain here, rather than on the page---at the time I made my edit, there did not seem to be much controversy, and there was no discussion here, so I didn't really think anyone cared all that much.


 * With regard to the series that Farnsworth presents, it seems that the show tells us that (a) every time the machine is used, it produces two copies of the original object, each at 60% scale, and it gives us no reason to believe that a duplicate duplicator would behave differently; (b) every Bender has a duplicator, which should produce 60% scale copies of the Bender making copies; and (c) for whatever reason, no Bender uses his duplicator more than once (I kind of assumed this is because Bender is really lazy, rather than because the machine only functions once). Even if we assume (as the most recent editor has) that (n+1)st generational Benders are 1/4 the mass of nth generational Benders, I don't see how we can reconcile the series that Farnsworth presents with the points above---there is an extra factor of n+1 in the denominator which does not make sense to me.


 * That being said, perhaps all of the mathematical wankery is not of general interest, and should be elided a bit in the actual entry. Perhaps something like this would be better:
 * The formula that Professor Farnsworth presents simplifies to the harmonic series multiplied by a constant. This series is divergent, though it is unclear how this is meant to model the infinitely multiplying Benders.
 * --134.197.0.22 16:51, 27 June 2011 (CEST) (and my IP at work is, of course, different from the one at home---I am the same as 71.83.120.33, above)