Difference between revisions of "User talk:San Saber"

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110011, by the way, turns out to be thirteen billion, one hundred ninety-four million, eight hundred ninety-four thousand, one hundred ninety-five (13,194,894,195) in binary. Each of the lines are 12, 18, 30, 33, 45, and then 51 from top to bottom. Also, it is symmetric, and if divided in half, the left side is the numbers from 1 through 6 (which is how I remembered it).
110011 the time code, by the way, turns out to be thirteen billion, one hundred ninety-four million, eight hundred ninety-four thousand, one hundred ninety-five (13,194,894,195) in binary. Each of the lines are 12, 18, 30, 33, 45, and then 51 from top to bottom. Also, it is symmetric, and if divided in half, the left side is the numbers from 1 through 6 (which is how I remembered it).

Revision as of 00:34, 15 October 2010

Beep

Please leave a message after the beep. San Saber 23:04, 4 October 2010 (CEST)

[BEEP!] Uh, hi, I... uh. call me. [CLICK!] Aki 16:00, 5 October 2010 (CEST)

Reply

You told me that you didn't understand my Goof in The Late Philip J. Fry . What it was, was that I suggested a way to get the time code back. Since the problem of the episode was to come back to 3010, I considered it a goof because no one used it.

Review of how to get the time code back:

Future Bender comes back from the future and tells Present Bender the time code. Present Bender jumps back in time, becoming "Future Bender", and gives Past Bender the time code, which would become "Present Bender" of that time. Now we are left with one Bender, with one time code.

Fun fact:

001100

010010

011110

100001

101101

110011 the time code, by the way, turns out to be thirteen billion, one hundred ninety-four million, eight hundred ninety-four thousand, one hundred ninety-five (13,194,894,195) in binary. Each of the lines are 12, 18, 30, 33, 45, and then 51 from top to bottom. Also, it is symmetric, and if divided in half, the left side is the numbers from 1 through 6 (which is how I remembered it).